Difference between revisions of "If the player spells a ten or more letter word, they should receive a 200 point bonus"

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(Syntax prettifying)
 
(2 intermediate revisions by one other user not shown)
Line 1: Line 1:
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Find the GetScoreForWord method. The for loop will calculate the score for the word played, the if statement adds any bonus points.
 +
 
<syntaxhighlight lang = csharp>
 
<syntaxhighlight lang = csharp>
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private static int GetScoreForWord(string Word, Dictionary<char, int> TileDictionary) {
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    int Score = 0;
 +
   
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    for (int Count = 0; Count < Word.Length; Count++) {
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        Score = Score + TileDictionary[Word[Count]];
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    }
 +
 +
    if (Word.Length > 7) {
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        Score = Score + 20;
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    } else if (Word.Length > 5) {
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        Score = Score + 5;
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    }
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    return Score;
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}
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</syntaxhighlight>
  
if (Word.Length > 10)
+
Change the if statement by adding a new condition, and change the current >7 condition to an else if instead. See below:
{
+
 
 +
<syntaxhighlight lang = csharp>
 +
if (Word.Length > 10)  
 
   score = score + 200;
 
   score = score + 200;
}
+
else if (Word.Length > 7)
 +
  Score = Score + 20;
 +
else if (Word.Length > 5)
 +
  Score = Score + 5;
 
</syntaxhighlight>
 
</syntaxhighlight>
oui
 

Latest revision as of 18:45, 14 November 2017

Find the GetScoreForWord method. The for loop will calculate the score for the word played, the if statement adds any bonus points.

private static int GetScoreForWord(string Word, Dictionary<char, int> TileDictionary) {
    int Score = 0;
    
    for (int Count = 0; Count < Word.Length; Count++) {
        Score = Score + TileDictionary[Word[Count]];
    }

    if (Word.Length > 7) {
        Score = Score + 20;
    } else if (Word.Length > 5) {
        Score = Score + 5;
    }
   
    return Score;
}

Change the if statement by adding a new condition, and change the current >7 condition to an else if instead. See below:

if (Word.Length > 10) 
  score = score + 200;
else if (Word.Length > 7)
  Score = Score + 20;
else if (Word.Length > 5)
  Score = Score + 5;