Difference between revisions of "Assembly Language Division"

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Line 1: Line 1:
  1      INP R0,2
+
  1      MOV R0, #20
  2      INP R1,2
+
  2      MOV R1, #3
  3      MOV R2,#0
+
  3      MOV R2, #0
 
  4 LOOP:SUB R0,R0,R1
 
  4 LOOP:SUB R0,R0,R1
 
  5      ADD R2,R2,#1
 
  5      ADD R2,R2,#1
Line 9: Line 9:
 
  9      SUB R2,R2,#1
 
  9      SUB R2,R2,#1
 
  10    ADD R3,R0,R1
 
  10    ADD R3,R0,R1
  11 END:OUT R2,4
+
  11 END:HALT
12    OUT R3,4
 
13    HALT
 
  
 
Line 1 & 2 will get the two numbers to divide.
 
Line 1 & 2 will get the two numbers to divide.
Line 31: Line 29:
 
Line 10 is to workout the remainder.
 
Line 10 is to workout the remainder.
  
Line 11 is the end label and will output the answer.
+
Line 11 is the end label and will halt.
  
Line 12 will output the remainder.
+
R2 will contain the result of the integer division.
  
Line 13 is the halt.
+
R3 will contain the remainder.

Latest revision as of 13:16, 21 January 2020

1      MOV R0, #20
2      MOV R1, #3
3      MOV R2, #0
4 LOOP:SUB R0,R0,R1
5      ADD R2,R2,#1
6      CMP R0,#0
7      BGT LOOP
8      BEQ END
9      SUB R2,R2,#1
10     ADD R3,R0,R1
11 END:HALT

Line 1 & 2 will get the two numbers to divide.

Line 3 will clear register 2 and make sure its set to zero.

Line 4 is the loop label and it will subtract the second number from the first.

Line 5 will increment register 2 to count the number of subtractions we make.

Line 6 compares register 0 with zero.

Line 7 if the compare is greater than we still have subtractions to make.

Line 8 if the compare was equal, then we have completed and the number divides exactly.

Line 9 is reached if the compare was less than zero, so the last subtraction was one too far, so minus 1 from register 2.

Line 10 is to workout the remainder.

Line 11 is the end label and will halt.

R2 will contain the result of the integer division.

R3 will contain the remainder.